Mathematics for Common Schools Volume 2 (Paperback)

This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1895 edition. Excerpt: ...How many square feet of plastering will there be on the walls and ceiling, deducting for a baseboard 12 inches wide? How many running feet of baseboard will be needed? Draw "development" of the above room, showing the four walls and the ceiling, and locating the doors, the windows, and the baseboard. Do not use baseboard where it is not required. 16. At the rate of $1,400 for a pile of lumber 25 ft. long, 20 ft. wide, 10 ft. high, what is the value of a pile 50 ft. long, 40 ft. wide, 20 ft. high? 17. If it costs $ 14 to paint the walls and the ceiling of a room 25 ft. long, 20 ft. wide, and 10 ft. high, what will it cost to paint the walls and the ceiling of a room 50 ft. long, 40 ft. wide, and 20ft. high? 1036. The sign of square root is-/. V81 = 9. Vl21=? V25=? V49=? 1037. Find the square root of 169. 10' = 100. 20'=400. The square root is between 10 and 20; it is, therefore, 10 + a second number. 169-102 + 2(10 x second) + second'. 169 = 100 + 20 x second + second'. 20 x second + second2 = 69. From this it appears that the second number is 3, since 20 x 3 + 32 = 69. 1038. It may be shown in this way: 10 (first number) 169 10' = 100 Trial divisor--twice 10 20) 69(3 second number) 60 9 3-= 9 Ant. 10 + 3 = 13. 1039. Find the square root of 2,116. 40 (first number) 2,116 40' 1,600 40 x 2 = 80, trial divisor ) 516(6 second number) 480 36 = 6' Ant. 46. 1040. Instead of multiplying the trial divisor by the second number, and then ascertaining whether the remainder is the square of the second number, the second number is added to the trial divisor and this sum is multiplied by the second number. 40 (first number) 2,116 1,600 1041. In practice, the work is shortened by omitting the ciphers. First, point off in periods of two figures, ...