Longmans' School Mensuration; With an Additional Chapter and Exercises (Paperback)


This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1897 Excerpt: ...for the pyramid. For, as the perimeter of a polygon, inscribed in a circle, becomes the circumference of the circle when the number of the sides of the polygon is increased indefinitely, so the cone may be regarded as a pyramid having for its base a polygon of an indefinite number of sides. Lateral surface of pyramid = perimeter of base x 8ant ne'gnt But perimeter of base of polygon)., of indefinite number of sides clrcumference of base of cone.-. Lateral surface of cone = c x--= 2-r x-= rrh 2 2 And total surface = r2 + nrh--mir + h) These are the results previously obtained. (c) To find the slant height, perpendicular height and radios of the cone being given. Let ABC be the cone. AO = perpendicular height = h. BO = radius of base-r. Then AB = slant height. AOB is a right-angled triangle..-. AB2 = OA2 + OB2.-. Slant height-= //7-2 + r2 Bule.--Take the square root of the sum of the squares of the perpendicular height and the radius of the base. (d) To find tho volume of a cone. The volume of a cone may be obtained from that of the pyramid. For it may be considered as a pyramid having an indefinite number of sides. Therefore the perimeter of the pyramid ultimately becomes the circumference of the cone. /. Volume of a cone = area of the base x one-third of the perpendicular height. Let r = radius of base, and h = perpendicular height..-. Volume = irr2 x n O Rule.--Multiply the area of the base by one-third of the perpendicular height. (See Easy Exercises XIII. And XIV.) EXERCISE XXVIII. 1. Find the lateral surface of a cone whose diameter is 17 ft. 2 in., and perpendicular height 21 ft. 2. How many yards of canvas f yd. wide will be required for a conical tent 20 ft. in diameter and 15 ft. high? 3. Find the volume of a cone the radius of whose base ...

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This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1897 Excerpt: ...for the pyramid. For, as the perimeter of a polygon, inscribed in a circle, becomes the circumference of the circle when the number of the sides of the polygon is increased indefinitely, so the cone may be regarded as a pyramid having for its base a polygon of an indefinite number of sides. Lateral surface of pyramid = perimeter of base x 8ant ne'gnt But perimeter of base of polygon)., of indefinite number of sides clrcumference of base of cone.-. Lateral surface of cone = c x--= 2-r x-= rrh 2 2 And total surface = r2 + nrh--mir + h) These are the results previously obtained. (c) To find the slant height, perpendicular height and radios of the cone being given. Let ABC be the cone. AO = perpendicular height = h. BO = radius of base-r. Then AB = slant height. AOB is a right-angled triangle..-. AB2 = OA2 + OB2.-. Slant height-= //7-2 + r2 Bule.--Take the square root of the sum of the squares of the perpendicular height and the radius of the base. (d) To find tho volume of a cone. The volume of a cone may be obtained from that of the pyramid. For it may be considered as a pyramid having an indefinite number of sides. Therefore the perimeter of the pyramid ultimately becomes the circumference of the cone. /. Volume of a cone = area of the base x one-third of the perpendicular height. Let r = radius of base, and h = perpendicular height..-. Volume = irr2 x n O Rule.--Multiply the area of the base by one-third of the perpendicular height. (See Easy Exercises XIII. And XIV.) EXERCISE XXVIII. 1. Find the lateral surface of a cone whose diameter is 17 ft. 2 in., and perpendicular height 21 ft. 2. How many yards of canvas f yd. wide will be required for a conical tent 20 ft. in diameter and 15 ft. high? 3. Find the volume of a cone the radius of whose base ...

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Product Details

General

Imprint

Rarebooksclub.com

Country of origin

United States

Release date

March 2012

Availability

Supplier out of stock. If you add this item to your wish list we will let you know when it becomes available.

First published

March 2012

Authors

Dimensions

246 x 189 x 2mm (L x W x T)

Format

Paperback - Trade

Pages

44

ISBN-13

978-1-130-47534-0

Barcode

9781130475340

Categories

LSN

1-130-47534-4



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