This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1848 Excerpt: ...horse power, or where the motive power is mechanical. To ascertain the weight any given power would draw up, or down a plane: --Divide the power by the friction given in the ascending or descending tables, adding as many cyphers to the power for a dividend as there are decimals contained in the divisor, and the quotient will be the weight drawn up, or down the plane. Ex. 1. What weight will a tractive power of 150 lbs. draw up a plane of 1 in 340, the resistance being estimated = 240th part of the insistent weight? Look in the left side column of the first table for 40, and for 300 at the top, and where thes# columns meet will be found the resistance "00,711. then, 15000,000-7-00,711=21,097 lbs.=the weight drawn up the plane. Ex. 2. Suppose a horse to be employed on a gradient descending 1 in 250; that he exerts a tractive force of 150 lbs., and travels 20 miles per day (ten miles loaded and ten when empty).Weight of wagons Jth of the gross load, and of earth 28 cwt. per cubic yard. Friction on the level TJTJtn Part f tne gross lad-What will be the result of his day's work? Look in the left side column of the table in page 82 for 50, and for 200 at the top, and where these columns meet will be found the resistance 000,267. then 150-00,000-7-00,267=56,180 lbs.=the weight drawn down the plane at one time. and 56,180 X 10 miles loaded= 561,800 lbs., --th for wagons= 421,350 lbs. drawn one mile per day. and 421,350-r-2240=188-10 tons drawn one mile per day, or 421,350-7-3136=134-36 cubic yards drawn one mile per day.f When the weight which a tractive power will draw along a level is given to find the weight which it will draw up, or down any plane. Resist, on the level X given wt. i i. vt l A. .0 ia-R5E = weight which the tractive power will draw up, o...